Question

Identify the center, radius, domain and range of the circle eith equation. Make sure to scroll down through all thr answer choices

(x+2)^2+(y-5)^2 = 9​

Answer 1

Answer: Centre: (-2,5)

Radius = 3

so

Diameter = 6

Domain: (-5,1)

Range: (2,8)

Answer 2

The center of the circle is (-2, 5), the radius is 3, the domain is [-5, 1], and the range is [2, 8].

The given equation represents a circle in standard form:

(x + 2)^2 + (y - 5)^2 = 9

Comparing this with the standard form of a circle (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius, we can identify the following:

Center: (-2, 5)

Radius: 3 (square root of 9)

Domain: The x-coordinates of the circle range from -2 - 3 = -5 to -2 + 3 = 1, so the domain is [-5, 1].

Range: The y-coordinates of the circle range from 5 - 3 = 2 to 5 + 3 = 8, so the range is [2, 8].