Answer:
According to the balanced chemical equation, 2 moles of hydrogen gas (H2) react with 1 mole of oxygen gas (O2) to produce 2 moles of water (H2O). This means that the reaction between 3.0 moles of hydrogen gas and 1.8 moles of oxygen gas would produce 3.0 moles of water.
Here’s how we can calculate this: The limiting reactant in this reaction is hydrogen gas because it would be completely consumed before the oxygen gas. For every 2 moles of hydrogen gas consumed, 2 moles of water are produced. So, if 3.0 moles of hydrogen gas are consumed, (3.0 moles H2) * (2 moles H2O / 2 moles H2) = 3.0 moles of water would be produced.