64.0k views
0 votes
What is the range of y=x^2-8x+12

User Lukas Anda
by
7.1k points

2 Answers

5 votes

Answer:

-infinity < x < infinity

Explanation:

it has none.

User Vicky Vicent
by
8.6k points
0 votes

Answer:

-4 ≤ y < ∞

Explanation:

You want the range of the relation y = x² -8x +12.

Range

The range is the vertical extent of the graph. We recognize the graph will be a parabola that opens upward (the leading coefficient of the quadratic is positive). The range will extend to positive infinity.

The lower limit of the range will be the y-value of the vertex of the parabola. We can find that by rewriting the equation in vertex form.

y = (x² -8x) +12

y = (x² -8x +16) +12 -16

y = (x -4)² -4

Comparing this to the vertex form equation ...

y = (x -h)² +k . . . . . . . . . vertex (h, k)

we see that k = -4. The minimum value of y is -4, so ...

the range is -4 ≤ y < ∞

__

Additional comment

In interval notation, this is [-4, ∞). This could also be written as y ≥ -4.

<95141404393>

What is the range of y=x^2-8x+12-example-1
User Kuzdu
by
7.9k points

No related questions found