Question

find four consecutive odd integers. five times the second is equal to one more than eight times the smaller

Answer 1

3,5,7,9

Explanation:

Let x be an odd integer

given that, consider four consecutive odd integers, which are

x , (x +2), (x+4), (x+6)

Now we have to determine these odd integers such that five times the second is equal to one more than eight times the smaller

5(x+2) = 1 + 8x

5x + 10 = 1 + 8x

10 - 1 = 8x - 5x

9 = 3x

x = 3