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Help! What are the zeros of the function?

f(x) = X^2 + 14x -32

X1= _

X2 = _

User Headshota
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1 Answer

6 votes

Answer:


x_1=-16,\,x_2=2

Explanation:


f(x)=x^2+14x-32\\0=x^2+14x-32\\0=(x+16)(x-2)\\x_1=-16,\,x_2=2

User Ted Ballou
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