The vertex form of the equation of a parabola is y= (x-3)2 + 36. What is the standard form of the equation? A. y=x2+x+18 B. y=x+6x+36 C. y = 3x² - 6x +45 D. y=x²2-6x +45

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Humphrey · Answer 1 · 2024-07-21T15:38:34+0000

Answer:

y=x^2-6x+45 (choice D)

Explanation:

All you need to do is expand the vertex form.

$y=(x-3)^2+36\\y=x^2-6x+9+36\\y=x^2-6x+45$

If you need further explanation, let me know.

Hope this helps!

The vertex form of the equation of a parabola is y= (x-3)2 + 36. What is the standard form of the equation? A. y=x2+x+18 B. y=x+6x+36 C. y = 3x² - 6x +45 D. y=x²2-6x +45

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The vertex form of the equation of a parabola is y= (x-3)2 + 36. What is the standard form of the equation? A. y=x2+x+18 B. y=x+6x+36 C. y = 3x² - 6x +45 D. y=x²2-6x +45​

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The vertex form of the equation of a parabola is y= (x-3)2 + 36. What is the standard form of the equation? A. y=x2+x+18 B. y=x+6x+36 C. y = 3x² - 6x +45 D. y=x²2-6x +45