Question

Kyle has 47 watermelons, 28 of them are green and 19 of them are yellow. If Kyle randomly eats one watermelon today, and one watermelon tomorrow, what is the probability that both watermelons will be green?

options:

0.28

0.35

0.56

1 because yellow watermelons do not exist

Answer 1

Hey there Vivi

Step-by-step explanation:

The probability of both watermelons being green can be calculated by dividing the number of favorable outcomes (both watermelons being green) by the total number of possible outcomes (any two watermelons chosen).

Kyle has 28 green watermelons out of a total of 47 watermelons. After eating one watermelon today, there will be 46 watermelons left, with 27 of them being green. Tomorrow, after eating one more watermelon, there will be 45 watermelons left, with 26 of them being green.

The probability of both watermelons being green is therefore (27/46) * (26/45) = 0.35.

Therefore, the correct option is 0.35.

Answer 2

To find the probability that both watermelons will be green, we need to calculate the probability of selecting a green watermelon on the first day and then selecting another green watermelon on the second day. The probability is approximately 0.29.

Step-by-step explanation:

To find the probability that both watermelons will be green, we need to calculate the probability of selecting a green watermelon on the first day and then selecting another green watermelon on the second day.

Probability of selecting a green watermelon on the first day = number of green watermelons / total number of watermelons = 28 / 47.

Probability of selecting a green watermelon on the second day = number of green watermelons remaining / total number of watermelons remaining = 27 / 46.

To find the probability of both events happening, we multiply the probabilities together: (28/47) * (27/46) = 0.286 or approximately 0.29.

Therefore, the probability that both watermelons will be green is approximately 0.29.