To solve this problem, we need to set up a system of equations to represent the given information. Let x be the price of one computer disk and y be the price of one notebook. Then we have:
2x + 3y = 22 (equation 1)
5x + 4y = 48 (equation 2)
To solve for x and y, we can use the method of elimination or substitution. Using the elimination method, we can multiply equation 1 by 2 and subtract it from equation 2 to eliminate x:
10x + 8y = 96 (equation 2 multiplied by 2)
-4x - 6y = -44 (equation 1 multiplied by -2)
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6x + 2y = 52
Simplifying, we get:
3x + y = 26 (equation 3)
We now have two equations with two unknowns:
2x + 3y = 22
3x + y = 26
Solving for y in the second equation, we get:
y = 26 - 3x
Substituting this into the first equation, we get:
2x + 3(26 - 3x) = 22
Simplifying and solving for x, we get:
x = 4
Substituting this value back into equation 3 to solve for y, we get:
y = 14/3
Therefore, the price of one computer disk is $4 and the price of one notebook is $14/3 or approximately $4.67.
Of the given choices, the correct solution is A. computer disk = $8; notebook = $2.