Question

Triangle KLM has KL=29​, KM=28​, and LM=22. What is the area of the​ triangle?

Answer 1

`\huge\boxed{\sf 288.9\ unit\²}`

Explanation:

Given that,

a = 29

b = 28

c = 22

Perimeter:

= Sum of all sides

= 29 + 28 + 22

= 79

Semi-perimeter:

= P / 2

= 79 / 2

= 39.5

Area of triangle:

Using heron's formula:

=
`√(s(s-a)(s-b)(s-c))`

Where s is semi-perimeter.

Put the given data:

=
`√(39.5(39.5-29)(39.5-28)(39.5-22))`

=
`√(39.5(10.5)(11.5)(17.5))`

=
`√(83468.4)`

≈ 288.9 unit²

`\rule[225]{225}{2}`