Answer:
1521.4545 J/kg⁰C
Step-by-step explanation:
The heat capacity of water is 4184 j/kg⁰C
Heat transferred(Q)=mass(m)*specific heat capacity(c)*temperature change(ΔT)
Q=mcΔT
Heat lost my copper is Q₁=0.4×c×110=44c
Heat gained by water is Q₂=0.8×4184×20=66944J
Let us assume there is no heat loss in the container.
Hence we have Q₁=Q₂
44c=66944
c=66944/44=1521.4545 J/kg⁰C
Hence the specific heat of copper rod is 1521.4545 J/kg⁰C