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Determine the equation of the circle with center (-2,-2)(−2,−2) containing the point (-7,-14)(−7,−14).

User Wingblade
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1 Answer

6 votes

Answer:

(x +2)² +(y +2)² = 169

Explanation:

You want the equation of a circle centered at (-2, -2) containing point (-7, -14).

Circle

The equation of a circle with center (h, k) and radius r is ...

(x -h)² +(y -k)² = r²

Using the given center, this is ...

(x +2)² +(y +2)² = r²

Point

We can find the value of r² by substituting the given point for (x, y):

(-7 +2)² +(-14 +2)² = r²

(-5)² +(-12)² = 25 +144 = 169 = r²

The equation of the circle is ...

(x +2)² +(y +2)² = 169

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Determine the equation of the circle with center (-2,-2)(−2,−2) containing the point-example-1
User John Farkerson
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