Question

A marshmallow peep contains 0.16-L at STP. The marshmallow peep is then placed in a vacuum and the pressure is reduced to 0.43 atm. What is the new volume of the marshmallow peep?

Answer 1

To find the new volume of the marshmallow peep after being placed in a vacuum, we can use Boyle's Law, which states that the product of pressure and volume is constant at constant temperature.

According to Boyle's Law:

P₁V₁ = P₂V₂

Where:
P₁ = Initial pressure (STP) = 1 atm
V₁ = Initial volume (STP) = 0.16 L
P₂ = Final pressure (in the vacuum) = 0.43 atm
V₂ = Final volume (to be calculated)

Substituting the given values into the equation:

(1 atm)(0.16 L) = (0.43 atm)(V₂)

Simplifying the equation:

0.16 L = (0.43 atm)(V₂)

Now, solve for V₂:

V₂ = (0.16 L) / (0.43 atm)

V₂ ≈ 0.372 L

Therefore, the new volume of the marshmallow peep in the vacuum is approximately 0.372 L.