Question

Idaho gets out and closes the door behind her. She is in a room with one exit, and the lock requires a key. There's a table with a briefcase that is also locked. It has a three-digit combination. The first part of the combination is on a wheel with all 10 digits. The second wheel has only 5 digits, and the third has 3 digits. How many combinations are possible?

Answer 1

150

Explanation:

To determine the number of possible combinations for the briefcase, we need to multiply the number of options for each wheel.

The first wheel has 10 digits, so there are 10 possibilities.

The second wheel has 5 digits, so there are 5 possibilities.

The third wheel has 3 digits, so there are 3 possibilities.

To calculate the total number of combinations, we multiply the possibilities for each wheel:

10 × 5 × 3 = 150

Therefore, there are 150 possible combinations for the briefcase.

Answer 2

Answer: 150

Explanation:

I’m not completely sure, but this is going by my logic. The first one has ten digits and any of those ten digits could go with 1 digit from the 5 wheel, and 1 digit from the 3 wheel, so (I think) you have to multiply 10x5x3 to get the amount of possible combinations.

But, if this is wrong, please correct me! I love puzzles and just though this would be fun to try and figure out, I don’t want to spout out any mis or disinfo to anyone

But, in the case my answer’s right, hope this helped :D