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Solve the following equation for 8. Find the smallest positive degree value.

4(sin(0)2) = -6.25
59.4°
37.0⁰
25.9°
70.7°

1 Answer

1 vote

Answer:

Explanation:

To solve the equation 4(sin(θ)^2) = -6.25, we need to find the value of θ in degrees.

First, let's isolate the sine term by dividing both sides of the equation by 4:

sin(θ)^2 = -6.25/4

sin(θ)^2 = -1.5625

Next, we take the square root of both sides to eliminate the square:

sin(θ) = ±√(-1.5625)

Since we are looking for the smallest positive degree value, we only consider the positive square root:

sin(θ) = √(-1.5625)

Now, we need to find the angle whose sine equals √(-1.5625). However, the sine function is only defined for values between -1 and 1. Therefore, there is no real angle whose sine equals √(-1.5625).

As a result, there is no solution to the equation 4(sin(θ)^2) = -6.25, and none of the given answer choices (59.4°, 37.0⁰, 25.9°, 70.7°) are correct.

User Mohamed Mesalm
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