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Write an equation of the line that passes through (-9,-5) and is perpendicular to the line y=9/2x+2

User Amaury
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1 Answer

3 votes

Answer:

y = -2/9x - 7

Explanation:

The slopes of perpendicular lines are negative reciprocals of each other, as shown by the formula m2 = -1/m1, where

  • m2 is the slope of the line we're trying to find,
  • and m1 is the slope of the line we're given

The line y = 9/2x + 2 is in slope-intercept form (y = mx + b), where

  • m is the slope,
  • and b is the y-intercept

Step 1: Thus, our m1 value (the slope of the given line) is 9/2 and we can plug it into the perpendicular slope formula to find m1 (the slope of the line we're trying to find):

m2 = -1 / (9/2)

m2 = -1 * 2/9

m2 = -2/9

Thus, the slope of the second line is -2/9.

Step 2: We can find b, the y-intercept of the second line by using the slope-intercept form and plugging in (-9, -5) for x and y and -2/9 for m:

-5 =-2/9(-9) + b

-5 = 18/9 + b

-5 = 2 + b

-7 = b

Thus, the y-intercept of the second line is -7

Thus, the equation of the line that passes through (-9, -5) and is perpendicular to the line y = 9/2x + 2 is y = -2/9x - 7

User Sriharsha
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