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What is the equation of a line perpendicular to 4x+3y=15 that goes through the point (5,2)?

User Peyotle
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1 Answer

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Answer:

y = (3/4)x - 7/4

Explanation:

y – y1 = m (x – x1), where y1 and x1 are the coordinates of a given point.

4x + 3y = 15

3y = -4x + 15

y = -(4/3)x + 5.

the slope of this line is -4/3.

the slope of the perpendicular line is -1 / (-4/3) = +3/4.

equation of perpendicular line through (5, 2) is:

y - 2 = (3/4) (x -5) = (3/4)x - (15/4)

y = (3/4)x - (15/4) + 2

y = (3/4)x - 7/4

User Roshith
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