Question

LHow many grams of lead (II) sulfate will precipitate out of solution when 90.0 mL of a 0.10M lead (II)

nitrate solution reacts with an excess of sulfuric acid? Nitric acid is another product of this reaction.

___Pb(NO3)2+____H2SO4–>____PbSO4+____HNO3

Answer 1

Answer: 2.73 g PbSO4

Step-by-step explanation:

1) solvefor moles Pb(no3)2

0.10 M X 0.09 L =0.009 moles Pb(NO3)2

2) stoichiometry from balanced chemical equation

___Pb(NO3)2 + ___H2SO4---> PbSO4 + ___2 HNO3

0.009 moles Pb(NO3)2 X (1 mole PbSO4 / 1 mole Pb(NO3)2) X (303.2516 g PBSO4/ 1mole PbSO4) = 2.73 g PbSO4