139k views
5 votes
How many atoms are in 94 g of NaCl

1 Answer

4 votes

Answer: 9.78 X 10^223 atoms NaCl

Step-by-step explanation:

Solve using Stoichiometry.

94 g NaCl X (1mole NaCl/58 gNaCl) X (6.02 X 10^23 atoms NaCl/1mole NaCl) = 9.78 X 10^23 atoms NaCl

User MarcSB
by
8.8k points

No related questions found