Answer: 9.78 X 10^223 atoms NaCl
Step-by-step explanation:
Solve using Stoichiometry.
94 g NaCl X (1mole NaCl/58 gNaCl) X (6.02 X 10^23 atoms NaCl/1mole NaCl) = 9.78 X 10^23 atoms NaCl
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