Question

A 1.30 L balloon is taken from room temperature (25*C) and placed into a freezer at -11.5*C.

What is its new volume? (isobaric change)

Answer 1

Step-by-step explanation:

To determine the new volume of the balloon after the temperature change, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature at constant pressure.

Let's assume the pressure remains constant during the temperature change. The initial volume is 1.30 L, and the initial temperature is 25°C (which needs to be converted to Kelvin).

Given:

Initial volume (V1) = 1.30 L

Initial temperature (T1) = 25°C = 25 + 273.15 = 298.15 K

Final temperature (T2) = -11.5°C = -11.5 + 273.15 = 261.65 K

Using Charles's Law equation:

(V1 / T1) = (V2 / T2)

We can rearrange the equation to solve for the new volume (V2):

V2 = (V1 * T2) / T1

Substituting the given values into the equation:

V2 = (1.30 L * 261.65 K) / 298.15 K

Calculating:

V2 = (340.045 L * K) / 298.15 K

V2 = 1.141 L (rounded to three decimal places)

Therefore, the new volume of the balloon after being placed in the freezer at -11.5°C is approximately 1.141 L.