Question

State the equation of a line that passes through the origin and is parallel to the line whose equation is shown below. Discuss and justify the steps taken to create this equation. 2y + 36 = -8x

Answer 1

y=-4x

2y + 36 = -8x

first, we want to put this in the equation of a circle which is y= mx+c, to do this we want to divide what we have by 2 giving us y + 18 =-4x, then rearrange so we have y on its own, so we subtract 18 which gives us the completed equation of the equation, y = -4x -18

using this we can begin to create our answer, since we know the gradient, is -4 and we know that the gradient of a parallel line is the same we can say that so far y = -4x , now we need the y intercept, since it intersects the origin it is 0, therefore our answer is y=-4x