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A nurse in a large university (N=30000) is concerned about students eye health. She takes a random sample of 75 students who don’t wear glasses and finds 27 that need glasses.

What the point estimate of p, the population proportion?
Whats the critical z value for a 90% confidence interval for the population proportion?
Whats the margin of error for a 90% confidence interval for the population proportion?
Calculate the 90% confidence interval for the population proportion.
Using your graphing calculator find a 95% confidence interval for the proportion of students who need to wear glasses but done. Show all work.
The nurse wants to be able to estimate, with a 95% confidence interval and a margin of error of 6% the proportion of students who need to wear glasses but don’t. Fine the necessary sample size (n) for this estimate.

User Mpaton
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1 Answer

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a) p^ = 27/75 = 0.36

User Rubens
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