137k views
3 votes
Solve the system of equations using elimination.

4x + 4y = 28
3x + y = 15
O (1,6)
O (2,5)
O (3, 4)
O (4,3)

User Nella
by
7.9k points

2 Answers

3 votes

Answer:

(4, 3)

Explanation:

i got it right on my quiz

Solve the system of equations using elimination. 4x + 4y = 28 3x + y = 15 O (1,6) O-example-1
User FacelessPanda
by
7.7k points
3 votes

Answer: (4, 3)

Explanation:

To solve the system of equations using elimination, we can manipulate the equations to eliminate one variable and solve for the other.

Let's start with the given system of equations:

Equation 1: 4x + 4y = 28

Equation 2: 3x + y = 15

To eliminate the y variable, we can multiply Equation 2 by 4 to make the coefficients of y in both equations the same:

4 * (3x + y) = 4 * 15

12x + 4y = 60

Now we have two equations with the same coefficient for y:

Equation 1: 4x + 4y = 28

Equation 3: 12x + 4y = 60

We can subtract Equation 1 from Equation 3 to eliminate the y variable:

Equation 3 - Equation 1:

(12x + 4y) - (4x + 4y) = 60 - 28

12x - 4x = 32

8x = 32

x = 4

Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use Equation 2:

3x + y = 15

3(4) + y = 15

12 + y = 15

y = 15 - 12

y = 3

Therefore, the solution to the system of equations is x = 4 and y = 3. So the answer is (4, 3).

User APoC
by
8.2k points

No related questions found