Question

Find the probability that a randomly selected point within the circle falls in the red-shaded square.

4√2
8
8
P = [ ? ]

Answer 1

0.64

Explanation:

Area of circle = π r ²

= π (4√2)²

= (4² X √2²) π

= 32π.

area of square = 8 X 8 = 64.

we want P(inside red square)

= 64/(32π)

= 0.64 to nearest one hundredth