Question

What volume in liters of H2 gas would be produced by the complete reaction of 2.93 g of Al solid at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. 2 Al(s) + 6 HCI (aq) → 2 AICI: (aq) + 3 H2 (9)

Answer 1

To find the volume of H2 gas produced, calculate the moles of H2 produced using stoichiometry. Then, use the ideal gas law to find the volume at STP.

Step-by-step explanation:

To find the volume of H2 gas produced, we need to first calculate the moles of H2 produced from 2.93 g of Al. To do this, we need to use stoichiometry to convert grams of Al to moles of H2 using the balanced equation. The molar mass of Al is 26.98 g/mol and the molar mass of H2 is 2.02 g/mol.

First, calculate the moles of Al:

2.93 g Al * (1 mol Al / 26.98 g Al) = 0.1083 mol Al

According to the balanced equation, 2 moles of Al react to form 3 moles of H2. So, the moles of H2 produced is:

0.1083 mol Al * (3 mol H2 / 2 mol Al) = 0.1625 mol H2

Finally, we can use the ideal gas law to find the volume of H2 gas at STP:

0.1625 mol H2 * (22.4 L / 1 mol) = 3.64 L H2

Answer 2

To find the volume of H₂ gas produced, we first need to calculate the number of moles of H2 produced from the given mass of Al using stoichiometry. The molar volume of any ideal gas at STP is 22.4 L/mol.

Step-by-step explanation:

To find the volume of H₂ gas produced, we first need to calculate the number of moles of H2 produced from the given mass of Al using stoichiometry. The molar mass of Al is 26.98 g/mol, so the number of moles of Al is 2.93 g / 26.98 g/mol = 0.1084 mol. From the balanced equation, we can see that 2 moles of Al produces 3 moles of H₂. Therefore, 0.1084 mol of Al produces (3/2) * 0.1084 mol = 0.1626 mol of H₂.

Now, we can use the ideal gas law, PV = nRT, to find the volume of H₂ at STP. The molar volume of any ideal gas at STP is 22.4 L/mol. The molar volume is a conversion factor that relates volume and moles of a gas. Therefore, 0.1626 mol of H₂ occupies 0.1626 mol * 22.4 L/mol = 3.63904 L of volume.

In conclusion, the complete reaction of 2.93 g of Al solid at STP would produce a volume of 3.63904 L of H₂ gas.