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1 vote
A student has 40 dimes and nickels. Their total value is $2.95. If

de number of dimes and n= number of nickels, this system of equations
represents the situation:
d+n=40
0.10d+0.05n 2.95
How many of each type of coin are there? Solve the system to answer the
question.
A. 10 dimes and 30 nickels
B. 21 dimes and 19 nickels
C. 19 dimes and 21 nickels
D. 20 dimes and 20 nickels

1 Answer

2 votes
Answer: C. 19 Dimes and 21 Nickels

19 x .10 = 1.90$
21 x .05 = 1.05$
1.90 + 1.05= 2.95$


1 dime is .10 (10 cents)
1 nickel is .05 (5 cents)
User Renaldo Balaj
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