Answer:
0.768 mol/L
Step-by-step explanation:
Given, mass of CsF = 58.4 gm
Molar mass of CsF = Molar mass of Cs + Molar mass of F
= 133 u + 19 u
= 152 u
Number of moles of CsF = Mass of CsF/ Molar mass of CsF
= 58.4/152 mol
Given, volume of solution = 500 mL = 0.5 L
Molarity of solution = moles of solute/volume of solution
= (58.4/152) mol / 0.5 L
= 58.4 * 2/152 mol/L
= 0.768 mol/L