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a square pyramid has a slant height of 3 in. and a surface area of 40 in.2. what is the length of an edge of the base, in inches?

User Sevenate
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1 Answer

1 vote

Answer:

4 inches

Explanation:

slant height = 3, surface area = 40.

let L = length of one side (since it's a square, it will be L for each edge of the base).

surface area = base + 4 sides of triangles

= L² X 4 (0.5 X base X height)

= L² X 4(0.5 X L X 3)

= L²+ 6L.

But surface area = 40.

So L² + 6L = 40.

Subtract 40 from both sides:

L² + 6L - 40 = 0.

Use the quadratic formula:

L = ((-b ± √(b² - 4ac)) ÷ 2a)

where a is the value of the first coefficient, b is value of the second and c is value of the constant.

L = ((-6 ± √(6² - 4(1)(-40))) ÷ 2(1))

= ((-6 ± √(36 + 160)) ÷ 2)

= (-6 ± 14) ÷ 2

= (-6 + 14) ÷ 2 or (-6 - 14) ÷ 2

= 4 or -10.

So L = 4 or -10. But L is a length, so it must be positive. So L = 4.

Length = 4 inches

User Deneil
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