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The difference between the roots of the equation 3x^2+bx+10=0 is equal to 4 1/3. FInd b

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Answer:

the value of b is 3√5

Explanation:

To find the value of b, we can use the quadratic formula which is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

Here, a = 3, b = b and c = 10.

Let the roots of the equation be α and β, such that α > β.

We know that α - β = 4 1/3 or 13/3.

Using the sum and product of roots formula, we have:

α + β = -b/a ...(1)

αβ = c/a = 10/3 ...(2)

Squaring equation (1), we get:

(α + β)^2 = b^2/a^2

Substituting the values of (1) and (2), we get:

(b^2/9) = (13/3)^2 - 4(10/3)

Solving this equation, we get:

x = -21 or x = 5

Since b is a real number, we can discard the negative value of x. Therefore,

b = √(5*9) = 3√5

Therefore, the value of b is 3√5.

User Shane Haw
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