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sodium reacts with water to produce sodium hydroxide and hydrogen gas. calculate the volume of hydrogen gas produced at 88.9 kpa and 34 degrees celsius when 4.78g of sodium is reacted

User Dewsworld
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The balanced chemical equation for the reaction of sodium with water is:

2Na + 2H2O → 2NaOH + H2

From the equation, we can see that 2 moles of sodium react to produce 1 mole of hydrogen gas.

To calculate the volume of hydrogen gas produced, we need to use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of hydrogen gas produced. We know that 2 moles of sodium produce 1 mole of hydrogen gas, so:

1 mole H2 = 2 moles Na

4.78 g Na x (1 mol Na / 23 g Na) x (1 mol H2 / 2 mol Na) = 0.104 mol H2

Next, we need to convert the temperature from Celsius to Kelvin:

T = 34°C + 273.15 = 307.15 K

Finally, we can use the ideal gas law to calculate the volume of hydrogen gas produced:

V = nRT/P

V = (0.104 mol)(0.08206 L·atm/mol·K)(307.15 K) / (88.9 kPa)

V = 0.00358 L or 3.58 mL (rounded to two significant figures)

Therefore, when 4.78g of sodium reacts with water at 88.9 kPa and 34 degrees Celsius, 3.58 mL of hydrogen gas is produced.

User Andree Wille
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