Question

A 60-kg passenger is in an elevator which is initially at rest. The elevator starts to travel downward. It reaches a downward speed of 7m/sec in a time of 4 seconds

Answer 1

a. Acceleration = 1.75 m/s²

b. Force = 105 Newton.

Step-by-step explanation:

Given the following data:

Mass = 60kg

Final velocity = 7m/s

Time = 4 seconds

Required to find the acceleration and force of the body;

a. To find the acceleration;

Mathematically, acceleration is given by the equation;

`Acceleration (a) = (final \; velocity - initial \; velocity)/(time)`

Where;

• a is acceleration measured in
  `ms^(-2)`
• v and u is final and initial velocity respectively, measured in
  `ms^(-1)`
• t is time measured in seconds.

Since the elevator is starting from rest, its initial velocity is equal to 0m/s.

Substituting into the equation, we have;

`Acceleration = (7 - 0)/(4)`

`Acceleration = (7)/(4)`

Acceleration = 1.75 m/s²

b. To find the force;

`Force = mass * acceleration`

Substituting into the equation, we have;

`Force = 60 * 1.75`

Force = 105 Newton.