Answer:
Explanation:
By first glance, you can see that in line CHF, it has two given and one unknown angle. The total angle of one straight line is 180. Given that:
a = 180 - 50 -70 = 60
The angle intersecting the CHFD line can be computed by the the total angle inside the triangle. Angle on EFH would give 180-40-60 = 80 and on EFD the angle would be 100 from 180-80. Since angle C is congruent to the angle EFD.
c = 100
Take note that in a 4 sided polygon (GEFH), the total exterior angle is 360 degrees.
The different angle would be
angle GHF = 50 + a = 50+60 = 110
angle EFH = 80
angle FEG = 180- c = 180-100 = 80
ANGLE EGH = 360 - GHF -EFH -FEG = 360 - 110-80-80 = 90
since angle AG is congruent to EGH, we can calculate for the angle b which is congruent to its opposite. This would give us formula of
360 = (90+90) + (b) +(b)
360 = 180 +2b
b = 90