Question

A ball is projected with velocity 10 m/sec at angle of 30 deg  with the horizontal surface. The time taken by ball to reach the ground is ?

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Answer 1

Step-by-step explanation:

Initial vertical velocity = 10 m/s sin 30

then gravity starts to slow it down:

v= 10 sin 30 - a t where a = 9.81 m/s^2

v = 10 sin 30 - 9.81 t when velocity = 0 the ball starts back down and takes the same amount of time to come back down from this height

0 = 10 sin30 - 9.81 t shows t = .509 s

Double this for the time when it has come back down and hits the ground = 1.02 s