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10 in.

11 in.
5.6 in.
10 in.
A. 444 in²
B. 544 in2
C. 644 in2
D. 780 in²

10 in. 11 in. 5.6 in. 10 in. A. 444 in² B. 544 in2 C. 644 in2 D. 780 in²-example-1
User Rosary
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1 Answer

2 votes

Answer:

I, B

Explanation:

You want the surface area of the triangular prism and the composite cuboid+pyramid figures shown.

Prism

The surface area is the area of the two bases plus the lateral area of the rectangular faces.

SA = bh +PH

SA = (8 ft)(6 ft) +(8 ft +6 ft +10 ft)(12 ft) = 48 ft² +(24 ft)(12 ft) = 336 ft²

The surface area of the prism is 336 square feet. (choice I)

Pyramid

The surface area of this figure is the sum of the areas of the square base, the lateral area of the cuboid, and the later area of the triangular faces.

SA = s² +4sh +2sH

SA = (10 in)² +4(10 in)(5.6 in) + 2(10 in)(11 in)

SA = 100 in² +224 in² +220 in² = 544 in²

The area of the pyramid figure is 544 square inches. (choice B)

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User SteveLambert
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