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Given tan theta = -5/2
and cos theta =2/√29
find csc theta:

User Sandia
by
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1 Answer

4 votes

Answer:
-(√(29))/(5)\\\\

This is the same as writing -sqrt(29)/5

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Step-by-step explanation:

tan(theta) < 0 and cos(theta) > 0 indicates angle theta is in quadrant IV.

In this quadrant, csc(theta) is negative.

The diagram is shown in the image below. We have these three sides

  • opposite = -5
  • adjacent = 2
  • hypotenuse =
    √(29)

Cosecant is the ratio of hypotenuse over opposite. It is the reciprocal of sine.


\csc(\theta) = \frac{\text{hypotenuse}}{\text{opposite}}\\\\\csc(\theta) = (√(29))/(-5)\\\\\csc(\theta) = -(√(29))/(5)\\\\

Given tan theta = -5/2 and cos theta =2/√29 find csc theta:-example-1
User Real Quick
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7.8k points