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Find an exponential function, algebraically, of the form y=ab^x whose graph passes through the given points: (2,6)(4,150)

with work please!!

1 Answer

2 votes

Answer:


y=(6)/(25)(5)^x or
y=0.24(5)^x

Explanation:

You know two points, so make two equations:


6=ab^2


150=ab^4

Solving for
a in the first equation, we have
\displaystyle a=(6)/(b^2), so this value can be plugged into the second equation to solve for
b:


\displaystyle 150=ab^4\\\\150=\biggr((6)/(b^2)\biggr)b^4\\\\150=6b^2\\\\25=b^2\\\\5=b

Thus, we can now find the value of
a given that
b=5 using either equation (I'll use the first one since it's easier):


\displaystyle 6=ab^2\\6=a(5)^2\\6=25a\\a=(6)/(25)=0.24

Hence, the exponential function whose graph passes through the given points is
\displaystyle y=(6)/(25)(5)^x, or
y=0.24(5)^x. I've attached a Desmos graph, and the regression confirms this answer is correct.

Find an exponential function, algebraically, of the form y=ab^x whose graph passes-example-1
User Ajay Bhojak
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