Question

Please help me with these math problems. Please also explain how to do them.

Answer 1

9) JI=41

8) A

Explanation:

Question 1:

We know that DE=GF, so that means that HJ=JI.

We can substitute in the values into an equivalent equation:

3x+20=15x-64

solve for x by adding 64 to both sides

3x+84=15x

subtract 3x from both sides

84=12x

divide both sides by 12

x=7

Then we can substitute 7 for x in the equation:

15x-64

15(7)-64

simplify

41

So, JI=41

Question 2:

The general (standard) form of an equation is:

`(x-h)^(2) + (x-k)^(2) =r^(2)`

with (h,k) being the center of the circle.

From the graph given, we can see that the center of the circle is at (-3,-3), and the radius is 4.

We can substitute in these values:

(x+3)²+(x+3)²=16

So, the correct answer would be A.

Hope this helps! :)