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Use the parabold tool to graph the quadratic function f(x) = 2x^2 + 16x + 30. find the vertex and another point for this function before you try to graph it! Graph the parabola by first plotting its vertex and then plotting a second point on the parabola

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Use the parabold tool to graph the quadratic function f(x) = 2x^2 + 16x + 30. find-example-1

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I can help guide you through the process of finding the vertex and another point for the function `f(x) = 2x^2 + 16x + 30` and then graphing it using a parabolic curve tool.

To find the vertex, we can use the formula:

Vertex = (-b/2a, f(-b/2a))

where the function is in the form f(x) = ax^2 + bx + c.

For the function f(x) = 2x^2 + 16x + 30, we have a = 2, b = 16, and c = 30.

The x-coordinate of the vertex is -b/2a, which in this case is:

x = -16/2(2) = -16/4 = -4

To find the y-coordinate of the vertex, we evaluate the function at x = -4:

f(-4) = 2(-4)^2 + 16(-4) + 30 = 2(16) - 64 + 30 = 32 - 34 = -2

Therefore, the vertex of the parabola is located at (-4, -2).

To find another point, we can simply choose any value of x and evaluate the function at that value. For example, let's choose x = 0:

f(0) = 2(0)^2 + 16(0) + 30 = 30
User Rushil Paul
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Answer:

vertex is : (-4 , -2)

Focus is : (-4 , -15/8)

User Cherrie Wilson
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