I can help guide you through the process of finding the vertex and another point for the function `f(x) = 2x^2 + 16x + 30` and then graphing it using a parabolic curve tool.
To find the vertex, we can use the formula:
Vertex = (-b/2a, f(-b/2a))
where the function is in the form f(x) = ax^2 + bx + c.
For the function f(x) = 2x^2 + 16x + 30, we have a = 2, b = 16, and c = 30.
The x-coordinate of the vertex is -b/2a, which in this case is:
x = -16/2(2) = -16/4 = -4
To find the y-coordinate of the vertex, we evaluate the function at x = -4:
f(-4) = 2(-4)^2 + 16(-4) + 30 = 2(16) - 64 + 30 = 32 - 34 = -2
Therefore, the vertex of the parabola is located at (-4, -2).
To find another point, we can simply choose any value of x and evaluate the function at that value. For example, let's choose x = 0:
f(0) = 2(0)^2 + 16(0) + 30 = 30