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David found a vintage watch his father lost 38 years ago. The watch’s date showed that it had worked for over two years after his father lost it. When David found the watch, it was 3 times as old as when his father lost it. How old was the watch when David’s father lost it?

User Lothric
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1 Answer

7 votes

Answer:

the watch was 1 year old when David's father lost it.

Explanation:

Let's break down the information given:David found the vintage watch 38 years after his father lost it.The watch's date showed that it had worked for over two years after his father lost it.When David found the watch, it was 3 times as old as when his father lost it.

Let's assume the age of the watch when David's father lost it as X years.According to the information, the watch worked for over two years after his father lost it. Therefore, we can represent the age of the watch when David found it as (X + 2) years.We are also given that when David found the watch, it was 3 times as old as when his father lost it. So we can write the equation:(X + 2) = 3XSimplifying the equation:

2 = 3X - X

2 = 2X

X = 1

User RyPope
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