Question

John has a cookie jar that contains 5 chocolate cookies, and 10 oatmeal cookies. He will draw two cookies from the jar one at a time without replacing the first cookie. What is the probability that John gets a chocolate cookie on his first draw and an oatmeal cookie on his second draw?

Answer 1

ughhhhh

Explanation:

To calculate the probability of John drawing a chocolate cookie on his first draw and an oatmeal cookie on his second draw without replacement, we need to consider the total number of cookies and the number of favorable outcomes.

Total number of cookies = 5 (chocolate) + 10 (oatmeal) = 15

For the first draw, John has 5 chocolate cookies out of 15 total cookies, so the probability of drawing a chocolate cookie on the first draw is 5/15.

After the first draw, there will be 14 cookies remaining in the jar (4 chocolate and 10 oatmeal).

For the second draw, John wants to draw an oatmeal cookie. Out of the 14 remaining cookies, there are 10 oatmeal cookies. So the probability of drawing an oatmeal cookie on the second draw, given that a chocolate cookie was drawn on the first draw, is 10/14.

To calculate the overall probability, we multiply the probabilities of each individual draw:

Probability = (5/15) * (10/14) = 50/210 = 5/21

Therefore, the probability that John gets a chocolate cookie on his first draw and an oatmeal cookie on his second draw is 5/21.