Question

Alice is x years younger than Bob, how old is Bob?

Answer 1

Answer: Z+Y-X

Step-by-step explanation: Alice is x years younger than Bob and y years younger than Charles. Diane is the youngest, and is z years younger than Bob. This shows that Charles is the oldest, Bob is the 2nd oldest and Alice is the 3rd oldest (or 2nd youngest). A function to solve this problem would be z+y-x, meaning if you add how much younger Diane is to Bob to how much younger Alice is to Charles, then you subtract how much younger Alice is to Bob you will get how much younger Diane is to Charles.

Answer 2

If Alice is x years younger than Bob, we need to know one more piece of information to determine Bob's age. One common way to set up this type of problem is to use one variable to represent Bob's age and another variable to represent Alice's age. We can then use the fact that Alice is x years younger than Bob to set up an equation that relates their ages.

Let's suppose that Bob's age is b, and Alice's age is a. If Alice is x years younger than Bob, then we can write:

a = b - x

This equation tells us that Alice's age is equal to Bob's age minus x. We can use this equation to solve for Bob's age.

Adding x to both sides of the equation, we get:

b = a + x

So Bob's age is equal to Alice's age plus x. This equation tells us that we need to know Alice's age in order to determine Bob's age. If we are given Alice's age, we can use this equation to find Bob's age. For example, if Alice is 20 years old and x = 5, then Bob is 25 years old.