Question

3.What is the equation of a circle with diameter AB, where A = (-1, 2) and B = (7, 8)?


A (x 3)2 + (y - 5)2 = 5
B (x - 3)2 + ( - 5)2 - 25
C (x+12+(- 72 = 100
D (x + 3)2 + (y + 5)2 - 25

Answer 1

Answer: (x−a)^2 + (y−b)^2 = r^2

Step-by-step explanation:BC is tangent to circle A at B and to circle D at C (not drawn to scale). AB=7, BC= 18, and DC = 5. Find AD to the nearest tenth. B