Question

What is (8n2-26n+20)/(n-2)

Answer 1

`2(4n-5)`

Explanation:

We start with this equation:

`(8n^2-26n+20)/(n-2)`

Factoring it out gives us:

`(2(4n-5)(n-2))/((n-2))`

Thus you can cancel the
`(n-2)` as:

`((n-2))/((n-2)) = 1`

Giving us:

`2(4n-5)`

Answer 2

2(4n -5)

Explanation:

Factorizing:

8n² - 26n + 20 = 2*(4n² - 13n + 10)

4n² - 13n + 10

Sum = -13

Product = 10 * 4 = 40

The factors should be in such a way that when we add, we should get (-13) and when we multiply, we should get 40.

Factors = (-8); (-5) { (-8) + (-5) = -13 & (-5)*(-8) = 40}

4n² - 13n + 40 = 4n² - 8n - 5n + 10 {Rewrite the middle term using the factors}

Take the common term 4n from the first two terms and (-5) from the third and fourth term.

= 4n(n - 2) -5 (n - 2)

= (n -2) (4n - 5)

`\sf (8n^2 - 26n + 20)/(n -2)= (2*(4n^2 - 13n +10))/((n -2))`

`= (2*(n -2)(4n -5))/((n -2))\\\\= 2*(4n-5)`