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If a chemist wishes to produce 500 mL of 2.0 M HCl, how much concentrated 12 M HCl should he measure out? (dilution problem)

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To solve the dilution problem, we can use the formula:

C₁V₁ = C₂V₂

Where:

C₁ is the initial concentration,

V₁ is the initial volume,

C₂ is the final concentration, and

V₂ is the final volume.

Given:

C₁ = 12 M (concentration of the concentrated HCl),

V₂ = 500 mL (final desired volume),

C₂ = 2.0 M (final desired concentration).

Let's solve for V₁:

C₁V₁ = C₂V₂

(12 M)(V₁) = (2.0 M)(500 mL)

Cross multiplying:

12V₁ = 2.0 × 500

12V₁ = 1000

V₁ = 1000 / 12

V₁ ≈ 83.33 mL

Therefore, the chemist should measure out approximately 83.33 mL of concentrated 12 M HCl to produce 500 mL of 2.0 M HCl.

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