Question

PLEASE HEL[P!!!!!!!!!!!!!!

The manufacturer of a generic medication claims the drug has as much active ingredient as the best-selling name brand, a mean of 150 mg per tablet. A consumer research group had a random sample of the generic drug tested. The results are shown below. Find the mean and standard deviation of the sample.

A. mean: 150.77; standard deviation: 7.32
B. mean: 150.77; standard deviation: 6.78
C. mean: 149.81; standard deviation: 6.78
D. mean: 149.81; standard deviation: 7.32

Answer 1

A

Explanation:

here are the numbers:

162, 140, 142, 140, 155, 152, 159, 157, 152, 156, 145, 159, 152, 140, 154, 155, 155, 159, 138, 161, 147, 148, 153, 141, 153, 143, 161, 142, 146, 156

sum = 4523

mean = sum/count = 4523/30 = 150.77

standard deviation =
`√((sum(x^2) - n*mean^2)/(n))`

= √((683527-30*4523²)/30) = 7.32