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determine whether the series is absolutely convergent, conditionally convergent, or divergent. sum_(n=0)^infinity (-14)^n/n!

User WeAreRight
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Answer:

Absolutely Convergent

yw;)

Explanation:

To determine whether the series is absolutely convergent, we can consider the absolute value of its terms: |(-14)^n/n!| = 14^n/n!. This is the Taylor series expansion for e^(14), which also converges. Therefore, the original series is absolutely convergent.

User Caknia
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