Final answer:
The maximum current delivered by an AC source connected across a 3.70-µF capacitor is approximately 1.145 A.
Step-by-step explanation:
The maximum current delivered by an AC source connected across a 3.70-µF capacitor can be determined using the formula:I = δVmax × 2πfC
Where:
I = Current
δVmax = Maximum voltage amplitude = 52.6 V
f = Frequency = 76.0 Hz
C = Capacitance = 3.70 µF
Plugging in the given values, we get:
I = 52.6 * 2π * 76.0 * 3.70 * 10^-6
I ≈ 1.145 A
Therefore, the maximum current delivered by the AC source is approximately 1.145 A.