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Lola and Dillon both went bowling last weekend, but not together. Lola went during open bowling time, paying $5 for shoe rental and $1 per hour, Dillon went on family night, when each hour was $2 and shoe rental was $1. As it turned out, they played for the same number of hours and spent the same amount. How much did each one spend? If you answer it, can you please do step-by-step explanation

User Carebear
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1 Answer

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To solve the problem, we need to use algebraic equations. Let's start by defining some variables:

- Let x be the number of hours they played.

- Let L be the total amount Lola spent.

- Let D be the total amount Dillon spent.

Using this notation, we can translate the problem into two equations:

L = 1x + 5

D = 2x + 1

The first equation represents Lola's expenses, which include $5 for shoe rental plus $1 per hour played. The second equation represents Dillon's expenses, which include $1 for shoe rental plus $2 per hour played.

We know that they played for the same number of hours and spent the same amount, so we can set L equal to D and solve for x:

L = D

1x + 5 = 2x + 1

x = 4

Now that we know they played for 4 hours, we can substitute x=4 into either equation to find out how much they spent:

L = 1(4) + 5 = $9

D = 2(4) + 1 = $9

Therefore, Lola and Dillon each spent $9 on bowling.

User Douglas Bagnall
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