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How many grams of CaF2 are present in 1.25L of a 0.15 M solution of CaF2?

1 Answer

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To solve this problem, we can use the formula:

moles of solute (CaF2) = concentration (in moles per liter) x volume (in liters)

First, we can calculate the number of moles of CaF2 in the solution:

moles of CaF2 = concentration x volume
moles of CaF2 = 0.15 mol/L x 1.25 L
moles of CaF2 = 0.1875 mol

Next, we can use the molar mass of CaF2 to convert moles to grams:

mass of CaF2 = moles of CaF2 x molar mass of CaF2
mass of CaF2 = 0.1875 mol x 78.08 g/mol
mass of CaF2 = 14.64 g

Therefore, there are 14.64 grams of CaF2 present in 1.25 L of a 0.15 M solution of CaF2.
User Geovanny
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