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5z + 3y = 4
-2x -8y = 6​

5z + 3y = 4 -2x -8y = 6​-example-1
User Yuva Raj
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Answer:

To eliminate a variable, you need to choose a strategy that allows you to add or subtract the equations in such a way that one variable will be eliminated. Let's go through the given options to determine the correct strategy:

A. Multiply the first equation by 2. Then add the equations.

If you multiply the first equation by 2, you get 10x + 6y = 8. If you add this equation to the second equation, you will not be able to eliminate either variable, as the coefficients of x and y do not match.

B. Multiply the first equation by 5 and the second equation by 2. Then add the equations.

If you multiply the first equation by 5, you get 25x + 15y = 20. If you multiply the second equation by 2, you get -4x - 16y = 12. Adding these equations gives you 21x - y = 32. This strategy allows you to eliminate y.

C. Multiply the second equation by 5. Then add the equations.

If you multiply the second equation by 5, you get -10x - 40y = 30. If you add this equation to the first equation, you will not be able to eliminate either variable, as the coefficients of x and y do not match.

D. Multiply the first equation by 2 and the second equation by 5. Then add the equations.

If you multiply the first equation by 2, you get 10x + 6y = 8. If you multiply the second equation by 5, you get -10x - 40y = 30. Adding these equations gives you -34y = 38. This strategy allows you to eliminate x.

Based on the options given, the correct strategy to eliminate a variable in this system of equations is: B.) Multiply the first equation by 5 and the second equation by 2. Then add the equations.

User Yaron Levi
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