Final answer:
The question involves finding the sample size needed for the t-distribution critical value to approximate that of the normal distribution for 90%, 95%, and 99% confidence intervals in estimating a population mean. Statistical software would be needed to calculate these specific sample sizes.
Step-by-step explanation:
The question seeks to determine sample size for achieving a t-distribution critical value that's within 0.01 of the normal distribution's critical value for different confidence levels for estimating a population mean.
For a 90% confidence interval, we want to capture the central 90% of the probability distribution. Using a z-score for a normal distribution, the critical value is 1.645. Using a t-distribution, we must determine the sample size where the critical t-value is within 0.01 of 1.645.
For 95% and 99% confidence intervals, the process is similar. First, we establish the normal distribution's z-scores for 95% (1.96) and 99% (2.576) confidence intervals. Then, we look for the respective t-distribution sample sizes where the critical t-values approximate the z-scores within 0.01.
Since the question requires the use of software to find the exact sample sizes, we must rely on statistical software or functions within a graphing calculator to derive these values. As we do not perform actual software calculations here, we cannot provide specific values, but the method involves inputting the confidence level and the desired proximity to the z-score to find the necessary sample size, which usually increases with a narrower gap between the t-value and the z-score.
It's important to note that historically, a rule of thumb was to use the Student's t-distribution for sample sizes up to 30 and the normal approximation for larger samples. However, with modern technology, the t-distribution is usually preferred when the population standard deviation is unknown, regardless of the sample size.